(7x+2)(3x^3-14x-5)=0

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Solution for (7x+2)(3x^3-14x-5)=0 equation: 


Simplifying
(7x + 2)(3x3 + -14x + -5) = 0

Reorder the terms:
(2 + 7x)(3x3 + -14x + -5) = 0

Reorder the terms:
(2 + 7x)(-5 + -14x + 3x3) = 0

Multiply (2 + 7x) * (-5 + -14x + 3x3)
(2(-5 + -14x + 3x3) + 7x * (-5 + -14x + 3x3)) = 0
((-5 * 2 + -14x * 2 + 3x3 * 2) + 7x * (-5 + -14x + 3x3)) = 0
((-10 + -28x + 6x3) + 7x * (-5 + -14x + 3x3)) = 0
(-10 + -28x + 6x3 + (-5 * 7x + -14x * 7x + 3x3 * 7x)) = 0
(-10 + -28x + 6x3 + (-35x + -98x2 + 21x4)) = 0

Reorder the terms:
(-10 + -28x + -35x + -98x2 + 6x3 + 21x4) = 0

Combine like terms: -28x + -35x = -63x
(-10 + -63x + -98x2 + 6x3 + 21x4) = 0

Solving
-10 + -63x + -98x2 + 6x3 + 21x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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